fix(mb): rank release groups by credited artist, not title alone

The worker MB resolver picked release groups on (title_ratio, is_album)
and never scored the artist — even though resolve() knows the followed
artist. For a generic title, same-titled release groups by *different*
artists tie on title, and the is_album tiebreak (added in 06e7f91 for
Off the Wall) then actively preferred a foreign Album over the correct
release. Concretely, following Lake Street Dive's "Fun Machine" EP
resolved to an unrelated band "Bastards of Melody"'s same-titled Album,
which then propagated as the downloaded/imported artist.

Make credited-artist similarity the primary sort key, above title and
above is_album. It's a soft signal, never a hard filter, so credited-
name variations (feat., punctuation) still resolve; is_album now only
breaks ties within the same artist+title, preserving the Off the Wall
fix. Verified live: resolve("Lake Street Dive", "Fun Machine") now
returns the 6-track LSD EP.

Co-Authored-By: Claude Opus 4.8 (1M context) <noreply@anthropic.com>

worker/lyra_worker/_musicbrainz.py

@@ -13,15 +13,39 @@ def _is_album(g: dict) -> bool:
     return (g.get("primary-type") or "").casefold() == "album"
 
 
-def _best_release_group(album: str, groups: list) -> dict | None:
-    """Choose the best release-group match for `album`. Highest title similarity wins;
-    an Album primary-type breaks ties so a famous album (e.g. Michael Jackson's "Off the
-    Wall") isn't resolved to its same-named single, whose short tracklist would then be
-    mapped positionally onto the full album's files. Returns None below the title threshold.
-    Pure — no network I/O."""
+def _credited_artist(g: dict) -> str:
+    """Primary credited artist name of a release-group search result, or '' if absent."""
+    credit = g.get("artist-credit")
+    if isinstance(credit, list) and credit and isinstance(credit[0], dict):
+        return (credit[0].get("artist") or {}).get("name", "") or ""
+    return ""
+
+
+def _best_release_group(artist: str, album: str, groups: list) -> dict | None:
+    """Choose the best release-group match for `artist`/`album`.
+
+    Ranked, highest first, on `(artist_ratio, title_ratio, is_album)`:
+      * artist match dominates — MusicBrainz relevance ties same-titled release groups by
+        *different* artists (e.g. "Fun Machine" exists as a Lake Street Dive EP and an
+        unrelated band's Album), and the artist we followed is trustworthy, so a credited
+        artist that matches the request outranks everything else;
+      * title similarity is next;
+      * an Album primary-type only breaks ties *within* the same artist+title, so a famous
+        album (Michael Jackson's "Off the Wall") still isn't resolved to its same-named
+        single whose short tracklist would map positionally onto the album's files.
+    Artist is a ranking signal, never a hard filter — a low match sinks a candidate but
+    never drops the release, so credited-name variations (feat., punctuation) still resolve.
+    Returns None below the title threshold. Pure — no network I/O."""
     if not groups:
         return None
-    best = max(groups, key=lambda g: (_ratio(album, g.get("title", "")), _is_album(g)))
+    best = max(
+        groups,
+        key=lambda g: (
+            _ratio(artist, _credited_artist(g)),
+            _ratio(album, g.get("title", "")),
+            _is_album(g),
+        ),
+    )
     if _ratio(album, best.get("title", "")) < _MIN_TITLE_RATIO:
         return None
     return best
@@ -46,7 +70,7 @@ class MusicBrainzResolver:
 
         res = musicbrainzngs.search_release_groups(query=album, artist=artist, limit=5)
         groups = res.get("release-group-list", [])
-        rg = _best_release_group(album, groups)
+        rg = _best_release_group(artist, album, groups)
         if rg is None:
             return None